mirror of
https://github.com/vsariola/sointu.git
synced 2025-05-25 18:00:37 -04:00
152 lines
5.4 KiB
Go
152 lines
5.4 KiB
Go
package vm
|
|
|
|
import "github.com/vsariola/sointu"
|
|
|
|
// findSuperIntArray finds a small super array containing all
|
|
// the subarrays passed to it. Returns the super array and indices where
|
|
// the subarrays can be found. For example:
|
|
// FindSuperIntArray([][]int{{4,5,6},{1,2,3},{3,4}})
|
|
// returns {1,2,3,4,5,6},{3,0,2}
|
|
// Implemented using a greedy search, so does not necessarily find
|
|
// the true optimal (the problem is NP-hard and analogous to traveling
|
|
// salesman problem).
|
|
//
|
|
// Used to construct a small delay time table without unnecessary repetition
|
|
// of delay times.
|
|
func findSuperIntArray(arrays [][]int) ([]int, []int) {
|
|
// If we go past MAX_MERGES, the algorithm could get slow and hang the computer
|
|
// So this is a safety limit: after this problem size, just merge any arrays
|
|
// until we get into more manageable range
|
|
const maxMerges = 1000
|
|
min := func(a int, b int) int {
|
|
if a < b {
|
|
return a
|
|
}
|
|
return b
|
|
}
|
|
overlap := func(a []int, b []int) (int, int) {
|
|
minShift := len(a)
|
|
for shift := len(a) - 1; shift >= 0; shift-- {
|
|
overlapping := true
|
|
for k := shift; k < min(len(a), len(b)+shift); k++ {
|
|
if a[k] != b[k-shift] {
|
|
overlapping = false
|
|
break
|
|
}
|
|
}
|
|
if overlapping {
|
|
minShift = shift
|
|
}
|
|
}
|
|
overlap := min(len(a)-minShift, len(b))
|
|
return overlap, minShift
|
|
}
|
|
sliceNumbers := make([]int, len(arrays))
|
|
startIndices := make([]int, len(arrays))
|
|
var processedArrays [][]int
|
|
for i := range arrays {
|
|
if len(arrays[i]) == 0 {
|
|
// Zero length arrays do not need to be processed at all
|
|
// They will 'start' at index 0 always as they have no length.
|
|
sliceNumbers[i] = -1
|
|
} else {
|
|
sliceNumbers[i] = len(processedArrays)
|
|
processedArrays = append(processedArrays, arrays[i])
|
|
}
|
|
}
|
|
if len(processedArrays) == 0 {
|
|
return []int{}, startIndices // no arrays with len>0 to process, just return empty array and all indices as 0
|
|
}
|
|
for len(processedArrays) > 1 { // there's at least two candidates that could be be merged
|
|
maxO, maxI, maxJ, maxS := -1, -1, -1, -1
|
|
if len(processedArrays) < maxMerges {
|
|
// find the pair i,j that results in the largest overlap with array i coming first, followed by potentially overlapping array j
|
|
for i := range processedArrays {
|
|
for j := range processedArrays {
|
|
if i == j {
|
|
continue
|
|
}
|
|
overlap, shift := overlap(processedArrays[i], processedArrays[j])
|
|
if overlap > maxO {
|
|
maxI, maxJ, maxO, maxS = i, j, overlap, shift
|
|
}
|
|
}
|
|
}
|
|
} else {
|
|
// The task is daunting, we have over MAX_MERGES overlaps to test. Just merge two first ones until the task is more manageable size
|
|
overlap, shift := overlap(processedArrays[0], processedArrays[1])
|
|
maxI, maxJ, maxO, maxS = 0, 1, overlap, shift
|
|
}
|
|
for k := range sliceNumbers {
|
|
if sliceNumbers[k] == maxJ {
|
|
// update slice pointers to point maxI instead of maxJ (maxJ will be appended to maxI, taking overlap into account)
|
|
sliceNumbers[k] = maxI
|
|
startIndices[k] += maxS // the array j starts at index maxS in array i
|
|
}
|
|
if sliceNumbers[k] > maxJ {
|
|
// pointers maxJ reduced by 1 as maxJ will be deleted
|
|
sliceNumbers[k]--
|
|
}
|
|
}
|
|
// if array j was not entirely included within array j
|
|
if maxO < len(processedArrays[maxJ]) {
|
|
// append array maxJ to array maxI, without duplicating the overlapping part
|
|
processedArrays[maxI] = append(processedArrays[maxI], processedArrays[maxJ][maxO:]...)
|
|
}
|
|
// finally, remove element maxJ from processedArrays
|
|
processedArrays = append(processedArrays[:maxJ], processedArrays[maxJ+1:]...)
|
|
}
|
|
return processedArrays[0], startIndices // there should be only one slice left in the arrays after the loop
|
|
}
|
|
|
|
// constructDelayTimeTable tries to construct the delay times table abusing
|
|
// overlapping between different delay times tables as much as possible.
|
|
// Especially: if two delay units use exactly the same delay times, they appear
|
|
// in the table only once.
|
|
//
|
|
// Returns the delay time table and two dimensional array of integers where
|
|
// element [i][u] is the index for instrument i / unit u in the delay table if
|
|
// the unit was a delay unit. For non-delay untis, the element is just 0.
|
|
func constructDelayTimeTable(patch sointu.Patch, bpm int) ([]int, [][]int) {
|
|
ind := make([][]int, len(patch))
|
|
var subarrays [][]int
|
|
// flatten the delay times into one array of arrays
|
|
// saving the indices where they were placed
|
|
for i, instr := range patch {
|
|
ind[i] = make([]int, len(instr.Units))
|
|
for j, unit := range instr.Units {
|
|
// only include delay times for delays. Only delays should use delay
|
|
// times. Only delay times for enabled delay units should be in the
|
|
// table.
|
|
if unit.Type == "delay" && !unit.Disabled {
|
|
ind[i][j] = len(subarrays)
|
|
converted := make([]int, len(unit.VarArgs))
|
|
copy(converted, unit.VarArgs)
|
|
if unit.Parameters["notetracking"] == 2 {
|
|
for i, t := range converted {
|
|
delay := 44100 * 60 * t / 48 / bpm
|
|
if delay > 65535 {
|
|
delay = 65535
|
|
}
|
|
converted[i] = delay
|
|
}
|
|
}
|
|
subarrays = append(subarrays, converted)
|
|
}
|
|
}
|
|
}
|
|
delayTable, indices := findSuperIntArray(subarrays)
|
|
// cancel the flattening, so unitindices can be used to
|
|
// to find the index of each delay in the delay table
|
|
unitindices := make([][]int, len(patch))
|
|
for i, instr := range patch {
|
|
unitindices[i] = make([]int, len(instr.Units))
|
|
for j, unit := range instr.Units {
|
|
if unit.Type == "delay" && !unit.Disabled {
|
|
unitindices[i][j] = indices[ind[i][j]]
|
|
}
|
|
}
|
|
}
|
|
return delayTable, unitindices
|
|
}
|